8/3n^2=6

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Solution for 8/3n^2=6 equation:



8/3n^2=6
We move all terms to the left:
8/3n^2-(6)=0
Domain of the equation: 3n^2!=0
n^2!=0/3
n^2!=√0
n!=0
n∈R
We multiply all the terms by the denominator
-6*3n^2+8=0
Wy multiply elements
-18n^2+8=0
a = -18; b = 0; c = +8;
Δ = b2-4ac
Δ = 02-4·(-18)·8
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-24}{2*-18}=\frac{-24}{-36} =2/3 $
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+24}{2*-18}=\frac{24}{-36} =-2/3 $

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